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[1/3] sched: don't initialize alloc_state in build_sched_domains

Message ID df57734a075cc5ad130e1ae498702e24f2529ab8.1370861520.git.viresh.kumar@linaro.org
State Accepted
Headers show

Commit Message

Viresh Kumar June 10, 2013, 10:57 a.m. UTC
alloc_state will be overwritten by __visit_domain_allocation_hell() and so we
don't actually need to initialize alloc_state.

Signed-off-by: Viresh Kumar <viresh.kumar@linaro.org>
---
 kernel/sched/core.c | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)
diff mbox

Patch

diff --git a/kernel/sched/core.c b/kernel/sched/core.c
index 0623703..5faa748 100644
--- a/kernel/sched/core.c
+++ b/kernel/sched/core.c
@@ -5956,7 +5956,7 @@  struct sched_domain *build_sched_domain(struct sched_domain_topology_level *tl,
 static int build_sched_domains(const struct cpumask *cpu_map,
 			       struct sched_domain_attr *attr)
 {
-	enum s_alloc alloc_state = sa_none;
+	enum s_alloc alloc_state;
 	struct sched_domain *sd;
 	struct s_data d;
 	int i, ret = -ENOMEM;